Advertisements
Advertisements
प्रश्न
Solve the following equation for x:
`2^(5x+3)=8^(x+3)`
Advertisements
उत्तर
`2^(5x+3)=8^(x+3)`
`rArr2^(5x+3)=(2^3)^(x+3)`
`rArr2^(5x+3)=2^(3x+9)`
⇒ 5x + 3 = 3x + 9
⇒ 5x - 3x = 9 - 3
⇒ 2x = 6
⇒ x = 6/2
⇒ x = 3
APPEARS IN
संबंधित प्रश्न
Prove that:
`1/(1+x^(a-b))+1/(1+x^(b-a))=1`
Simplify the following:
`(6(8)^(n+1)+16(2)^(3n-2))/(10(2)^(3n+1)-7(8)^n)`
Solve the following equation for x:
`2^(3x-7)=256`
Prove that:
`(1/4)^-2-3xx8^(2/3)xx4^0+(9/16)^(-1/2)=16/3`
Show that:
`(x^(a^2+b^2)/x^(ab))^(a+b)(x^(b^2+c^2)/x^(bc))^(b+c)(x^(c^2+a^2)/x^(ac))^(a+c)=x^(2(a^3+b^3+c^3))`
Solve the following equation:
`sqrt(a/b)=(b/a)^(1-2x),` where a and b are distinct primes.
If a and b are distinct primes such that `root3 (a^6b^-4)=a^xb^(2y),` find x and y.
Simplify:
`root(lm)(x^l/x^m)xxroot(mn)(x^m/x^n)xxroot(nl)(x^n/x^l)`
(256)0.16 × (256)0.09
If \[4x - 4 x^{- 1} = 24,\] then (2x)x equals
