Advertisements
Advertisements
प्रश्न
Solve the following equation for x:
`2^(5x+3)=8^(x+3)`
Advertisements
उत्तर
`2^(5x+3)=8^(x+3)`
`rArr2^(5x+3)=(2^3)^(x+3)`
`rArr2^(5x+3)=2^(3x+9)`
⇒ 5x + 3 = 3x + 9
⇒ 5x - 3x = 9 - 3
⇒ 2x = 6
⇒ x = 6/2
⇒ x = 3
APPEARS IN
संबंधित प्रश्न
Assuming that x, y, z are positive real numbers, simplify the following:
`(sqrt2/sqrt3)^5(6/7)^2`
Find the value of x in the following:
`(root3 4)^(2x+1/2)=1/32`
If `3^(x+1)=9^(x-2),` find the value of `2^(1+x)`
Simplify:
`root(lm)(x^l/x^m)xxroot(mn)(x^m/x^n)xxroot(nl)(x^n/x^l)`
State the product law of exponents.
If (x − 1)3 = 8, What is the value of (x + 1)2 ?
When simplified \[( x^{- 1} + y^{- 1} )^{- 1}\] is equal to
If x-2 = 64, then x1/3+x0 =
When simplified \[\left( - \frac{1}{27} \right)^{- 2/3}\] is
If \[2^{- m} \times \frac{1}{2^m} = \frac{1}{4},\] then \[\frac{1}{14}\left\{ ( 4^m )^{1/2} + \left( \frac{1}{5^m} \right)^{- 1} \right\}\] is equal to
