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Solve each of the following system of equations in R. 5 x − 7 < 3 ( x + 3 ) , 1 − 3 x 2 ≥ x − 4

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प्रश्न

Solve each of the following system of equations in R.

\[5x - 7 < 3\left( x + 3 \right), 1 - \frac{3x}{2} \geq x - 4\]

 

संक्षेप में उत्तर
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उत्तर

\[5x - 7 < 3\left( x + 3 \right)\]
\[ \Rightarrow 5x - 7 < 3x + 9\]
\[ \Rightarrow 5x - 3x < 9 + 7\]
\[ \Rightarrow 2x < 16\]
\[ \Rightarrow x < 8\]
\[ \Rightarrow x \in \left( - \infty , 8 \right) . . . (i)\]
\[\text{ Also } , 1 - \frac{3x}{2} \geq x - 4\]
\[ \Rightarrow x - 4 \leq 1 - \frac{3x}{2}\]
\[ \Rightarrow x + \frac{3x}{2} \leq 1 + 4\]
\[ \Rightarrow \frac{2x + 3x}{2} \leq 5\]
\[ \Rightarrow 5x \leq 10 \]
\[ \Rightarrow x \leq 2 \]
\[ \Rightarrow x \in ( - \infty , 2] . . . (ii)\]
\[\text{ Hence, the solution of the given set of inequalities is theintersection of (i) and (ii) }  . \]
\[\left( - \infty , 8 \right) \cap ( - \infty , 2] = ( - \infty , 2]\]
\[\text{ Hence, the solution of the given set of inequalities is }  ( - \infty , 2] . \]

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अध्याय 15: Linear Inequations - Exercise 15.2 [पृष्ठ १५]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 15 Linear Inequations
Exercise 15.2 | Q 14 | पृष्ठ १५

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