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Find the graphical solution of the following system of linear inequations:x60+y90≤1, x120+y75≤1, y ≥ 0, x ≥ 0

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प्रश्न

Find the graphical solution of the following system of linear inequations:
`"x"/60 + "y"/90 ≤ 1`, `"x"/120 + "y"/75 ≤ 1`, y ≥ 0, x ≥ 0

योग
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उत्तर

Consider the equations:
`"x"/60 + "y"/90 ≤ 1`

x 60 0
y 0 90

The two points on the axes are (60, 0) and (0, 90) as in equation 60 and 90 are x and y-intercepts,
(x and y are equivalent to X and Y axes.)
∵ The inequation `"x"/60 + "y"/90 ≤ 1` satisfies the origin.
The solution set is towards the origin.
`"x"/120 + "y"/75 ≤ 1` 

x 120 0
y 0 75

The two points on the axes are (120, 0) and (0, 75) respectively.
The inequation `"x"/120 + "y"/75 ≤ 1` satisfies the origin.

The solution set of the inequation is towards origin x ≥ 0, y ≥0 are the inequations showing the conditions that the solutions set (common region) is in the first quadrant

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Linear Inequations - Exercise 8.3 [पृष्ठ १२१]

APPEARS IN

बालभारती Mathematics and Statistics (Commerce) Part 2 [English] Standard 11 Maharashtra State Board
अध्याय 8 Linear Inequations
Exercise 8.3 | Q 5 | पृष्ठ १२१

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