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प्रश्न
Find the graphical solution of the following system of linear inequations:
`"x"/60 + "y"/90 ≤ 1`, `"x"/120 + "y"/75 ≤ 1`, y ≥ 0, x ≥ 0
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उत्तर
Consider the equations:
`"x"/60 + "y"/90 ≤ 1`
| x | 60 | 0 |
| y | 0 | 90 |
The two points on the axes are (60, 0) and (0, 90) as in equation 60 and 90 are x and y-intercepts,
(x and y are equivalent to X and Y axes.)
∵ The inequation `"x"/60 + "y"/90 ≤ 1` satisfies the origin.
The solution set is towards the origin.
`"x"/120 + "y"/75 ≤ 1`
| x | 120 | 0 |
| y | 0 | 75 |
The two points on the axes are (120, 0) and (0, 75) respectively.
The inequation `"x"/120 + "y"/75 ≤ 1` satisfies the origin.
The solution set of the inequation is towards origin x ≥ 0, y ≥0 are the inequations showing the conditions that the solutions set (common region) is in the first quadrant
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