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Show that the function given by f(x) = sin x is a. strictly increasing in (0,π2) b. strictly decreasing in (π2,π) c. neither increasing nor decreasing in (0, π) - Mathematics

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प्रश्न

Show that the function given by f(x) = sin x is

  1. strictly increasing in `(0, pi/2)`
  2. strictly decreasing in `(pi/2, pi)`
  3. neither increasing nor decreasing in (0, π)
योग
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उत्तर

The given function is f(x) = sin x.

f'(x) = cos x

a. Since for each `x in (0, pi/2)`, cos x > 0, we have f'(x) > 0

Hence, f is strictly increasing in `(0. pi/2)`

b. Since for each `x in (pi/2 , pi), cos x < 0` we have f'(x) < 0

Hence, f is strictly decreasing in `(pi/2, pi)`

c.  From the results obtained in (a) and (b), it is clear that f is neither increasing nor decreasing in (0, π).

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Application of Derivatives - Exercise 6.2 [पृष्ठ २०५]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 6 Application of Derivatives
Exercise 6.2 | Q 3 | पृष्ठ २०५

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