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Relativistic corrections become necessary when the expression for the kinetic energy 12mv2, becomes comparable with mc2, where m is the mass of the particle. At what de Broglie - Physics

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प्रश्न

Relativistic corrections become necessary when the expression for the kinetic energy `1/2 mv^2`, becomes comparable with mc2, where m is the mass of the particle. At what de Broglie wavelength will relativistic corrections become important for an electron?

  1. λ = 10 nm
  2. λ = 10–1 nm
  3. λ = 10–4 nm
  4. λ = 10–6 nm

विकल्प

  • a and c

  • a and d

  • c and d

  • a and b

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उत्तर

c and d

Explanation:

De-Broglie or matter wave is independent of die charge on the material particle. It means matter wave of the de-Broglie wave is associated with every moving particle (whether charged or uncharged).

The de-Broglie wavelength at which relativistic corrections become important is that the phase velocity of the matter waves can be greater than the speed of the light (3 × 108 m/s).

The wavelength of de-Broglie wave is given by λ = h/p = h/mv

Here, h = 6.6 × 10-34 Js

And for electron, m = 9 × 10-31 kg

To approach these types of problems we use the hit and trial method by picking up each option one by one.

In option (a), λ1 = 10 nm = 10 × 10–9 m = 10–8 m

⇒ `v_1 = (6.6 xx 10^-34)/((9 xx 10^-31) xx 10^-8)`

= `2.2/3 xx 10^5 = 10^5` m/s

In option (b), λ2 = 10–1 nm = 10–1 × 10–9 m = 10–10 m

⇒ `v_2 = (6.6 xx 10^-34)/((9 xx 10^-31) xx 10^-10) = 10^7` m/s

In option (c), λ3 = 10–4 nm = 10–4 × 10–9 m = 10–13 m

⇒ `v_3 = (6.6 xx 10^-34)/((9 xx 10^-31) xx 10^-13) = 10^10` m/s

In option (d), λ4 = 10–6 nm = 10–6 × 10–9 m = 10–15 m

⇒ `v_4 = (6.6 xx 10^-34)/((9 xx 10^-31) xx 10^-15) = 10^12` m/s

Thus options (c) and (d) are correct as v3 and v4 is greater than 3 × 108 m/s.

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अध्याय 11: Dual Nature Of Radiation And Matter - Exercises [पृष्ठ ७०]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 12
अध्याय 11 Dual Nature Of Radiation And Matter
Exercises | Q 11.09 | पृष्ठ ७०

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