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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Show that the wavelength of electromagnetic radiation is equal to the de Broglie wavelength of its quantum (photon).

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प्रश्न

Show that the wavelength of electromagnetic radiation is equal to the de Broglie wavelength of its quantum (photon).

दीर्घउत्तर
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उत्तर

The momentum of a photon having energy (hv) is given as:

p = `(h v)/c`

= `h/lambda`

λ = `h/p`    ...(i)

Where,

λ = Wavelength of the electromagnetic radiation

c = Speed of light

h = Planck’s constant

De Broglie wavelength of the photon is given as:

λ = `h/(m v)`

But p = mv

∴ λ = `h/p`    ...(ii)

Where,

m = Mass of the photon

v = Velocity of the photon

Hence, it can be inferred from equations (i) and (ii) that the wavelength of the electromagnetic radiation is equal to the de Broglie wavelength of the photon.

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अध्याय 11: Dual Nature of Radiation and Matter - EXERCISES [पृष्ठ २८९]

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एनसीईआरटी Physics Part I and II [English] Class 12
अध्याय 11 Dual Nature of Radiation and Matter
EXERCISES | Q 11.11 | पृष्ठ २८९
एनसीईआरटी Physics Part I and II [English] Class 12
अध्याय 11 Dual Nature of Radiation and Matter
Exercise | Q 11.18 | पृष्ठ ४०८

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