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Show that the wavelength of electromagnetic radiation is equal to the de Broglie wavelength of its quantum (photon). - Physics

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प्रश्न

Show that the wavelength of electromagnetic radiation is equal to the de Broglie wavelength of its quantum (photon).

संख्यात्मक
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उत्तर

The momentum of a photon having energy (hv) is given as:

`p = (hv)/c = h/lambda`

`lambda = h/p` .....(i)

Where,

λ = Wavelength of the electromagnetic radiation

c = Speed of light

h = Planck’s constant

De Broglie wavelength of the photon is given as:

`lambda = h/(mv)`

But p = mv

∴ `lambda = h/p` .....(ii)

Where,

m = Mass of the photon

v = Velocity of the photon

Hence, it can be inferred from equations (i) and (ii) that the wavelength of the electromagnetic radiation is equal to the de Broglie wavelength of the photon.

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अध्याय 11: Dual Nature of Radiation and Matter - EXERCISES [पृष्ठ २८९]

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एनसीईआरटी Physics [English] Class 12
अध्याय 11 Dual Nature of Radiation and Matter
EXERCISES | Q 11.11 | पृष्ठ २८९

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