हिंदी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Show that the wavelength of electromagnetic radiation is equal to the de Broglie wavelength of its quantum (photon).

Advertisements
Advertisements

प्रश्न

Show that the wavelength of electromagnetic radiation is equal to the de Broglie wavelength of its quantum (photon).

दीर्घउत्तर
Advertisements

उत्तर

The momentum of a photon having energy (hv) is given as:

p = `(h v)/c`

= `h/lambda`

λ = `h/p`    ...(i)

Where,

λ = Wavelength of the electromagnetic radiation

c = Speed of light

h = Planck’s constant

De Broglie wavelength of the photon is given as:

λ = `h/(m v)`

But p = mv

∴ λ = `h/p`    ...(ii)

Where,

m = Mass of the photon

v = Velocity of the photon

Hence, it can be inferred from equations (i) and (ii) that the wavelength of the electromagnetic radiation is equal to the de Broglie wavelength of the photon.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Dual Nature of Radiation and Matter - EXERCISES [पृष्ठ २८९]

APPEARS IN

एनसीईआरटी Physics Part I and II [English] Class 12
अध्याय 11 Dual Nature of Radiation and Matter
EXERCISES | Q 11.11 | पृष्ठ २८९
एनसीईआरटी Physics Part I and II [English] Class 12
अध्याय 11 Dual Nature of Radiation and Matter
Exercise | Q 11.18 | पृष्ठ ४०८

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

What is the

(a) momentum,

(b) speed, and

(c) de Broglie wavelength of an electron with kinetic energy of 120 eV.


What is the de Broglie wavelength of a bullet of mass 0.040 kg travelling at the speed of 1.0 km/s?


An electron and a photon each have a wavelength of 1.00 nm. Find

(a) their momenta,

(b) the energy of the photon, and

(c) the kinetic energy of electron.


Obtain the de Broglie wavelength of a neutron of kinetic energy 150 eV. As you have an electron beam of this energy is suitable for crystal diffraction experiments. Would a neutron beam of the same energy be equally suitable? Explain. (mn= 1.675 × 10−27 kg)


The energy and momentum of an electron are related to the frequency and wavelength of the associated matter wave by the relations:

E = hv, p = `"h"/lambda`

But while the value of λ is physically significant, the value of v (and therefore, the value of the phase speed vλ) has no physical significance. Why?


The wavelength λ of a photon and the de-Broglie wavelength of an electron have the same value. Show that energy of a photon in (2λmc/h) times the kinetic energy of electron; where m, c and h have their usual meaning.


 Show with the help of a labelled graph how their wavelength (λ) varies with their linear momentum (p).


70 cal of heat is required to raise the temperature of 2 moles of an ideal gas at constant pressure from 30°C to 35°C. The amount of heat required to raise the temperature of the gas through the same range at constant volume will be (assume R = 2 cal/mol-K).


An electromagnetic wave of wavelength ‘λ’ is incident on a photosensitive surface of negligible work function. If ‘m’ mass is of photoelectron emitted from the surface has de-Broglie wavelength λd, then ______.


Relativistic corrections become necessary when the expression for the kinetic energy `1/2 mv^2`, becomes comparable with mc2, where m is the mass of the particle. At what de Broglie wavelength will relativistic corrections become important for an electron?

  1. λ = 10 nm
  2. λ = 10–1 nm
  3. λ = 10–4 nm
  4. λ = 10–6 nm

A particle moves in a closed orbit around the origin, due to a force which is directed towards the origin. The de Broglie wavelength of the particle varies cyclically between two values λ1, λ2 with λ1 > λ2. Which of the following statement are true?

  1. The particle could be moving in a circular orbit with origin as centre.
  2. The particle could be moving in an elliptic orbit with origin as its focus.
  3. When the de Broglie wavelength is λ1, the particle is nearer the origin than when its value is λ2.
  4. When the de Broglie wavelength is λ2, the particle is nearer the origin than when its value is λ1.

A proton and an α-particle are accelerated, using the same potential difference. How are the de-Broglie wavelengths λp and λa related to each other?


Assuming an electron is confined to a 1 nm wide region, find the uncertainty in momentum using Heisenberg Uncertainty principle (∆x∆p ≃ h). You can assume the uncertainty in position ∆x as 1 nm. Assuming p ≃ ∆p, find the energy of the electron in electron volts.


An alpha particle is accelerated through a potential difference of 100 V. Calculate:

  1. The speed acquired by the alpha particle, and
  2. The de-Broglie wavelength is associated with it.

(Take mass of alpha particle = 6.4 × 10−27 kg)


Given below are two statements:

Statement - I: Two photons having equal linear momenta have equal wavelengths.

Statement - II: If the wavelength of photon is decreased, then the momentum and energy of a photon will also decrease.

In the light of the above statements, choose the correct answer from the options given below.


The De-Broglie wavelength of electron in the third Bohr orbit of hydrogen is ______ × 10-11 m (given radius of first Bohr orbit is 5.3 × 10-11 m):


A particle of mass 4M at rest disintegrates into two particles of mass M and 3M respectively having non zero velocities. The ratio of de-Broglie wavelength of particle of mass M to that of mass 3M will be:


Which of the following graphs correctly represents the variation of a particle momentum with its associated de-Broglie wavelength?


How will the de-Broglie wavelength associated with an electron be affected when the accelerating potential is increased? Justify your answer.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×