हिंदी

Why Photoelectric Effect Cannot Be Explained on the Basis of Wave Nature of Light? Give Reasons.

Advertisements
Advertisements

प्रश्न

Why photoelectric effect cannot be explained on the basis of wave nature of light? Give reasons.

Advertisements

उत्तर

 Wave nature of radiation cannot explain the following:

(i) The instantaneous ejection of photoelectrons.

(ii) The existence of threshold frequency for a metal surface.

(iii) The fact that kinetic energy of the emitted electrons is independent of the intensity of light and depends upon its frequency.

Thus, the photoelectric effect cannot be explained on the basis of wave nature of light.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2012-2013 (March) Delhi Set 2

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

A proton and an α-particle have the same de-Broglie wavelength Determine the ratio of  their speeds.


For what kinetic energy of a neutron will the associated de Broglie wavelength be 1.40 × 10−10 m?


What is the de Broglie wavelength of a nitrogen molecule in air at 300 K? Assume that the molecule is moving with the root-mean square speed of molecules at this temperature. (Atomic mass of nitrogen = 14.0076 u)


Obtain the de Broglie wavelength of a neutron of kinetic energy 150 eV. As you have an electron beam of this energy is suitable for crystal diffraction experiments. Would a neutron beam of the same energy be equally suitable? Explain. (mn= 1.675 × 10−27 kg)


When a light wave travels from air to glass ______.


What are matter waves?


 Show with the help of a labelled graph how their wavelength (λ) varies with their linear momentum (p).


Assuming an electron is confined to a 1 nm wide region, find the uncertainty in momentum using Heisenberg Uncertainty principle (∆x∆p ≃ h). You can assume the uncertainty in position ∆x as 1 nm. Assuming p ≃ ∆p, find the energy of the electron in electron volts.


A particle of mass 4M at rest disintegrates into two particles of mass M and 3M respectively having non zero velocities. The ratio of de-Broglie wavelength of particle of mass M to that of mass 3M will be:


An electron of mass me, and a proton of mass mp = 1836 me are moving with the same speed. The ratio of the de Broglie wavelength `lambda_"electron"/lambda_"proton"` will be:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×