मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Show that the wavelength of electromagnetic radiation is equal to the de Broglie wavelength of its quantum (photon).

Advertisements
Advertisements

प्रश्न

Show that the wavelength of electromagnetic radiation is equal to the de Broglie wavelength of its quantum (photon).

दीर्घउत्तर
Advertisements

उत्तर

The momentum of a photon having energy (hv) is given as:

p = `(h v)/c`

= `h/lambda`

λ = `h/p`    ...(i)

Where,

λ = Wavelength of the electromagnetic radiation

c = Speed of light

h = Planck’s constant

De Broglie wavelength of the photon is given as:

λ = `h/(m v)`

But p = mv

∴ λ = `h/p`    ...(ii)

Where,

m = Mass of the photon

v = Velocity of the photon

Hence, it can be inferred from equations (i) and (ii) that the wavelength of the electromagnetic radiation is equal to the de Broglie wavelength of the photon.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 11: Dual Nature of Radiation and Matter - EXERCISES [पृष्ठ २८९]

APPEARS IN

एनसीईआरटी Physics Part I and II [English] Class 12
पाठ 11 Dual Nature of Radiation and Matter
EXERCISES | Q 11.11 | पृष्ठ २८९
एनसीईआरटी Physics Part I and II [English] Class 12
पाठ 11 Dual Nature of Radiation and Matter
Exercise | Q 11.18 | पृष्ठ ४०८

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

What is the de Broglie wavelength of a ball of mass 0.060 kg moving at a speed of 1.0 m/s?


Find the typical de Broglie wavelength associated with a He atom in helium gas at room temperature (27°C) and 1 atm pressure, and compare it with the mean separation between two atoms under these conditions.


Which one of the following deflect in electric field


A proton, a neutron, an electron and an α-particle have same energy. Then their de Broglie wavelengths compare as ______.


An electron (mass m) with an initial velocity `v = v_0hati` is in an electric field `E = E_0hatj`. If λ0 = h/mv0, it’s de Broglie wavelength at time t is given by ______.


Relativistic corrections become necessary when the expression for the kinetic energy `1/2 mv^2`, becomes comparable with mc2, where m is the mass of the particle. At what de Broglie wavelength will relativistic corrections become important for an electron?

  1. λ = 10 nm
  2. λ = 10–1 nm
  3. λ = 10–4 nm
  4. λ = 10–6 nm

Two particles A1 sand A2 of masses m1, m2 (m1 > m2) have the same de Broglie wavelength. Then ______.

  1. their momenta are the same.
  2. their energies are the same.
  3. energy of A1 is less than the energy of A2.
  4. energy of A1 is more than the energy of A2.

An alpha particle is accelerated through a potential difference of 100 V. Calculate:

  1. The speed acquired by the alpha particle, and
  2. The de-Broglie wavelength is associated with it.

(Take mass of alpha particle = 6.4 × 10−27 kg)


The ratio of wavelengths of proton and deuteron accelerated by potential Vp and Vd is 1 : `sqrt2`. Then, the ratio of Vp to Vd will be ______.


A particle of mass 4M at rest disintegrates into two particles of mass M and 3M respectively having non zero velocities. The ratio of de-Broglie wavelength of particle of mass M to that of mass 3M will be:


For which of the following particles will it be most difficult to experimentally verify the de-Broglie relationship?


In a Frank-Hertz experiment, an electron of energy 5.6 eV passes through mercury vapour and emerges with an energy 0.7 eV. The minimum wavelength of photons emitted by mercury atoms is close to ______.


Which of the following graphs correctly represents the variation of a particle momentum with its associated de-Broglie wavelength?


E, c and `v` represent the energy, velocity and frequency of a photon. Which of the following represents its wavelength?


The graph which shows the variation of `(1/lambda^2)` and its kinetic energy, E is (where λ is de Broglie wavelength of a free particle):


What is another name for matter waves?


Rearranging \[p=\frac{h}{\lambda}\] gives which expression?


Which phenomenon does the concept of matter waves help explain?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×