मराठी

An alpha particle is accelerated through a potential difference of 100 V. Calculate: (i) The speed acquired by the alpha particle, and (ii) The de-Broglie wavelength is associated with it. - Physics

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प्रश्न

An alpha particle is accelerated through a potential difference of 100 V. Calculate:

  1. The speed acquired by the alpha particle, and
  2. The de-Broglie wavelength is associated with it.

(Take mass of alpha particle = 6.4 × 10−27 kg)

संख्यात्मक
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उत्तर

(i) `1/2 "mv"^2` = qV

or, `1/2"mv"^2` = 2e × 100

or, mv2 = 400 eV

or, v = `sqrt((400  "eV")/"m")`

or, v = `sqrt((400 xx 1.6 xx 10^-19)/(6.4 xx 10^-27))`

∴ v = 105 m/s

(ii) de-Broglie wavelength = λ = `"h"/sqrt(2"mqV")`

or, λ = `(6.6 xx 10^-34)/(sqrt(2 xx 6.4 xx 10^-27 xx 2 xx 1.6 xx 10^-19 xx 100))`

∴ λ = 1.03 × 10−12 m

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2021-2022 (March) Term 2 - Delhi Set 2

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