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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Compute the typical de Broglie wavelength of an electron in a metal at 27°C and compare it with the mean separation between two electrons in a metal which is given to be about 2 × 10−10 m.

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प्रश्न

Compute the typical de Broglie wavelength of an electron in a metal at 27°C and compare it with the mean separation between two electrons in a metal which is given to be about 2 × 10−10 m.

संख्यात्मक
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उत्तर

Temperature, T = 27°C = 27 + 273 = 300 K

Mean separation between two electrons, r = 2 × 10−10 m

De Broglie wavelength of an electron is given as:

`lambda = "h"/sqrt(3"mkT")`

Where,

h = Planck’s constant = 6.6 × 10−34 Js

m = Mass of an electron = 9.11 × 10−31 kg

k = Boltzmann constant = 1.38 × 10−23 J mol−1 K−1

∴ `lambda = (6.6 xx 10^(-34))/sqrt(3 xx 9.11 xx 10^(-31) xx 1.38 xx 10^(-23) xx 300)`

≈ 6.2 × 10−9 m

Hence, the de Broglie wavelength is much greater than the given inter-electron separation.

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अध्याय 11: Dual Nature of Radiation and Matter - Exercise [पृष्ठ ४११]

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एनसीईआरटी Physics Part I and II [English] Class 12
अध्याय 11 Dual Nature of Radiation and Matter
Exercise | Q 11.36 | पृष्ठ ४११

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