हिंदी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

For what kinetic energy of a neutron will the associated de Broglie wavelength be 1.40 × 10−10 m?

Advertisements
Advertisements

प्रश्न

For what kinetic energy of a neutron will the associated de Broglie wavelength be 1.40 × 10−10 m?

संख्यात्मक
Advertisements

उत्तर

De Broglie wavelength of the neutron, λ = 1.40 × 10−10 m

Mass of a neutron, mn = 1.66 × 10−27 kg

Planck’s constant, h = 6.6 × 10−34 Js

Kinetic energy (K) and velocity (v) are related as:

`"K" = 1/2 "m"_"n""v"^2` …......(1)

De Broglie wavelength (λ) and velocity (v) are related as:

`lambda = "h"/("m"_"n""v")` ........(2)

Using equation (2) in equation (1), we get:

`"K" = 1/2 ("m"_"n""h"^2)/(lambda^2 "m"_"n"^2) = "h"^2/(2lambda^2"m"_"n")`

= `(6.63 xx 10^(-34))^2/(2xx(1.40 xx 10^(-10))^2 xx 1.66 xx 10^(-27))`

=  6.75 × 10−21 J

= `(6.75 xx 10^-21)/(1.6 xx 10^-19)`

= 4.219 × 10−2 eV

Hence, the kinetic energy of the neutron is 6.75 × 10−21 J or 4.219 × 10−2 eV.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Dual Nature of Radiation and Matter - Exercise [पृष्ठ ४०८]

APPEARS IN

एनसीईआरटी Physics Part I and II [English] Class 12
अध्याय 11 Dual Nature of Radiation and Matter
Exercise | Q 11.17 (a) | पृष्ठ ४०८

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Calculate the momentum of the electrons accelerated through a potential difference of 56 V.


Calculate the de Broglie wavelength of the electrons accelerated through a potential difference of 56 V.


The wavelength of light from the spectral emission line of sodium is 589 nm. Find the kinetic energy at which

(a) an electron, and

(b) a neutron, would have the same de Broglie wavelength.


What is the de Broglie wavelength of a ball of mass 0.060 kg moving at a speed of 1.0 m/s?


Find the de Broglie wavelength of a neutron, in thermal equilibrium with matter, having an average kinetic energy of `(3/2)` kT at 300 K.


Crystal diffraction experiments can be performed using X-rays, or electrons accelerated through appropriate voltage. Which probe has greater energy? (For quantitative comparison, take the wavelength of the probe equal to 1 Å, which is of the order of inter-atomic spacing in the lattice) (me = 9.11 × 10−31 kg).


Find the typical de Broglie wavelength associated with a He atom in helium gas at room temperature (27°C) and 1 atm pressure, and compare it with the mean separation between two atoms under these conditions.


Compute the typical de Broglie wavelength of an electron in a metal at 27°C and compare it with the mean separation between two electrons in a metal which is given to be about 2 × 10−10 m.


State any one phenomenon in which moving particles exhibit wave nature.


Describe briefly how the Davisson-Germer experiment demonstrated the wave nature of electrons.


What are matter waves?


The de-Broglie wavelength associated with a material particle when it is accelerated through a potential difference of 150 volt is 1 Å. What will be the de-broglie wavelength associated with the same particle when it is accelerated through a potential difference of 4500 V?


A proton, a neutron, an electron and an α-particle have same energy. Then their de Broglie wavelengths compare as ______.


Relativistic corrections become necessary when the expression for the kinetic energy `1/2 mv^2`, becomes comparable with mc2, where m is the mass of the particle. At what de Broglie wavelength will relativistic corrections become important for an electron?

  1. λ = 10 nm
  2. λ = 10–1 nm
  3. λ = 10–4 nm
  4. λ = 10–6 nm

An alpha particle is accelerated through a potential difference of 100 V. Calculate:

  1. The speed acquired by the alpha particle, and
  2. The de-Broglie wavelength is associated with it.

(Take mass of alpha particle = 6.4 × 10−27 kg)


The equation λ = `1.227/"x"` nm can be used to find the de Brogli wavelength of an electron. In this equation x stands for:

Where,

m = mass of electron

P = momentum of electron

K = Kinetic energy of electron

V = Accelerating potential in volts for electron


The ratio of wavelengths of proton and deuteron accelerated by potential Vp and Vd is 1 : `sqrt2`. Then, the ratio of Vp to Vd will be ______.


For which of the following particles will it be most difficult to experimentally verify the de-Broglie relationship?


In a Frank-Hertz experiment, an electron of energy 5.6 eV passes through mercury vapour and emerges with an energy 0.7 eV. The minimum wavelength of photons emitted by mercury atoms is close to ______.


How will the de-Broglie wavelength associated with an electron be affected when the velocity of the electron decreases? Justify your answer.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×