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Refer to Figure. Let ∆U1 And ∆U2 Be the Changes in Internal Energy of the System in the Process A And B. Then

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प्रश्न

Refer to figure. Let ∆U1 and ∆U2 be the changes in internal energy of the system in the process A and B. Then _____________ .

विकल्प

  • ∆U1 > ∆U2

  • ∆U1 = ∆U2

  • ∆U1 < ∆U2

  • ∆U1 ≠ ∆U2

MCQ
रिक्त स्थान भरें
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उत्तर

∆U1 = ∆U2

 

The internal energy of the system is a state function, i.e. it only depends on the initial and final point of the process and doesn't depend on the path followed. Both processes A and B have common initial and final points. Therefore, change in internal energy in process A is equal to the change in internal energy in process​ B. Thus,

∆U1 = ∆U2 = 0

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अध्याय 26: Laws of Thermodynamics - MCQ [पृष्ठ ६१]

APPEARS IN

एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 26 Laws of Thermodynamics
MCQ | Q 4 | पृष्ठ ६१

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