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Redefine the function which is given by f(x) = |x-1|+|1+x|,-2≤x≤2 - Mathematics

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प्रश्न

Redefine the function which is given by f(x) = `|x - 1| + |1 + x|, -2 ≤ x ≤ 2`

योग
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उत्तर

f(x) = `|x - 1| + |1 + x|, -2 ≤ x ≤ 2`

= `{(-x + 1 - 1 - x",", -2 ≤ x < -1),(-x + 1 + x + 1",", -1 ≤ x  < 1),(x - 1 + 1 + x",", 1 ≤ x ≤ 2):}`

= `{{:(-2x",", -2 ≤ x  < - 1),(2",", -1 ≤ x < 1),(2x",", 1 ≤ x ≤ 2):}`

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अध्याय 2: Relations and Functions - Solved Examples [पृष्ठ २५]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 2 Relations and Functions
Solved Examples | Q 9 | पृष्ठ २५
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