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प्रश्न
Find the range of the following functions given by `sqrt(16 - x^2)`
योग
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उत्तर
The domain of f
Where f(x) = `sqrt(16 - x^2)` is given by [– 4, 4]
For the range
Let y = `sqrt(16 - x^2)`
Then y2 = 16 – x2
or x2 = 16 – y2
Since x ∈ [– 4, 4]
Thus range of f = [0, 4]
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