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Prove the statement by using the Principle of Mathematical Induction: n(n2 + 5) is divisible by 6, for each natural number n.

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प्रश्न

Prove the statement by using the Principle of Mathematical Induction:

n(n2 + 5) is divisible by 6, for each natural number n.

प्रमेय
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उत्तर

P(n) = n(n2 + 5) is divisible by 6.

So, substituting different values for n, we get,

P(0) = 0(02 + 5) = 0 Which is divisible by 6.

P(1) = 1(12 + 5) = 6 Which is divisible by 6.

P(2) = 2(22 + 5) = 18 Which is divisible by 6.

P(3) = 3(32 + 5) = 42 Which is divisible by 6.

Let P(k) = k(k2 + 5) be divisible by 6.

So, we get,

⇒ k(k2 + 5) = 6x

Now, we also get that,

⇒ P(k + 1) = (k + 1)((k + 1)2 + 5) = (k + 1)(k2 + 2k + 6)

= k3 + 3k2 + 8k + 6

= 6x + 3k2 +3k + 6

= 6x + 3k(k + 1) + 6[n(n + 1) is always even and divisible by 2]

= 6x + 3 × 2y + 6 Which is divisible by 6.

⇒ P(k + 1) is true when P(k) is true.

Therefore, by Mathematical Induction,

P(n) = n(n2 + 5) is divisible by 6, for each natural number n.

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अध्याय 4: Principle of Mathematical Induction - Exercise [पृष्ठ ७१]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
अध्याय 4 Principle of Mathematical Induction
Exercise | Q 10 | पृष्ठ ७१

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