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Prove That: Sin 80° − Cos 70° = Cos 50° - Mathematics

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प्रश्न

Prove that:

sin 80° − cos 70° = cos 50°
योग
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उत्तर

Consider LHS: 
\[\sin 80^\circ - \cos 70^\circ\]
\[ = \sin 80^\circ - \cos \left( 90^\circ - 20^\circ \right)\]
\[ = \sin 80^\circ - \sin 20^\circ\]
\[ = 2\sin \left( \frac{80^\circ - 20^\circ}{2} \right) \cos \left( \frac{80^\circ + 20^\circ}{2} \right) \left\{ \because \sin A - \sin B = 2\sin \left( \frac{A - B}{2} \right) \cos \left( \frac{A + B}{2} \right) \right\}\]
\[ = 2\sin 30^\circ \cos 50^\circ\]
\[ = 2 \times \frac{1}{2}\cos 50^\circ\]
\[ = \cos 50^\circ\]
= RHS
Hence, LHS = RHS.

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Transformation Formulae
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Transformation formulae - Exercise 8.2 [पृष्ठ १७]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 8 Transformation formulae
Exercise 8.2 | Q 3.7 | पृष्ठ १७

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