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If α + β = π 2 , Show that the Maximum Value of Cos α Cos β is 1 2 .

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प्रश्न

If α + β = \[\frac{\pi}{2}\], show that the maximum value of cos α cos β is \[\frac{1}{2}\].

 

 

योग
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उत्तर

\[\frac{\pi}{2} = 90^\circ\]

\[\text{ Let }x = \cos \alpha \cos \beta\]

\[ \Rightarrow x = \frac{1}{2}\left[ 2\cos \alpha \cos \beta \right]\]

\[ \Rightarrow x = \frac{1}{2}\left[ \cos \left( \alpha + \beta \right) + \cos \left( \alpha - \beta \right) \right]\]

\[ \Rightarrow x = \frac{1}{2}\left[ \cos \left( \alpha - \beta \right) + \cos 90^\circ \right]\]

\[ \Rightarrow x = \frac{1}{2}\cos \left( \alpha - \beta \right)\]

Now,

\[ - 1 \leq \cos \left( \alpha - \beta \right) \leq 1\]

\[ \Rightarrow - \frac{1}{2} \leq \frac{1}{2}\cos\left( \alpha - \beta \right) \leq \frac{1}{2}\]

\[ \Rightarrow - \frac{1}{2} \leq x \leq \frac{1}{2}\]

\[ \Rightarrow - \frac{1}{2} \leq \cos \alpha \cos \beta \leq \frac{1}{2}\]

\[\text{Hence}, \frac{1}{2}\text{ is the maximum value of }\cos \alpha \cos \beta .\]

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Transformation Formulae
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Transformation formulae - Exercise 8.1 [पृष्ठ ७]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 8 Transformation formulae
Exercise 8.1 | Q 8 | पृष्ठ ७

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