हिंदी

Prove that: (cosx-cosy)2+(sinx-siny)2=4sin2 x-y2

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प्रश्न

Prove that: `(cos x - cosy)^2 + (sin x - sin y)^2 = 4 sin^2  (x - y)/2`

योग
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उत्तर

L.H.S. = (cos x – cos y)2 + (sin x – sin y)2

= `( -2sin  (x + y)/2  sin  (x - y)/2)^2 + (2cos  (x + y)/2  sin  (x -  y)/2)^2`

=  `4sin^2  (x +y)/2  sin^2  (x - y)/2 + 4cos^2  (x +y)/2  sin^2  (x - y)/2`

= `4sin^2 (x -y) [ sin^2  (x + y)/2 + cos^2  (x +y)/2]`

= `4sin^2  (x - y)/2`  `[∵ sin^2  (x  + y)/2 + cos^2  (x +y)/2 = 1]`

= R.H.S.

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अध्याय 3: Trigonometric Functions - Miscellaneous Exercise [पृष्ठ ७१]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 3 Trigonometric Functions
Miscellaneous Exercise | Q 4. | पृष्ठ ७१

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