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Prove the following: sin2 6x – sin2 4x = sin 2x sin 10x

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प्रश्न

Prove the following:

sin2 6x – sin2 4x = sin 2x sin 10x

योग
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उत्तर

sin26x – sin24x = (sin6x + sin4x) (sin 6x - sin 4x)

= `2sin  ((6x + 4x)/2) cos ((6x - 4 x) /2) 2 sin ((6x - 4x)/2) cos ((6x + 4x)/2)`

= (2sin5x cosx) (2cos 5x sinx)

= (2sin x cos x)(2sin 5x cos5x)

= sin 2x sin 10x

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अध्याय 3: Trigonometric Functions - EXERCISE 3.3 [पृष्ठ ६७]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 3 Trigonometric Functions
EXERCISE 3.3 | Q 12. | पृष्ठ ६७

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