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Prove that cos(A + B) cos C – cos(B + C) cos A = sin B sin(C – A)

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प्रश्न

Prove that cos(A + B) cos C – cos(B + C) cos A = sin B sin(C – A)

योग
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उत्तर

L.H.S = (cos A cos B – sin A sin B) cos C – (cos B cos C – sin B sin C) cos A

= cos A cos B cos C – sin A sin B cos C – cos A cos B cos C + cos A sin B sin C

= cos A sin B sin C – sin A sin B cos C

= sin B [sin C cos A – cos C sin A]

= sin B [sin (C – A)]

= R.H.S

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Trigonometric Functions and Their Properties
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometry - Exercise 3.4 [पृष्ठ १०९]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 3 Trigonometry
Exercise 3.4 | Q 14 | पृष्ठ १०९

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