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प्रश्न
Show that tan(45° + A) = `(1 + tan"A")/(1 - tan"A")`
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उत्तर
tan(45° + A) = `(tan45^circ + tan"A")/(1 - tan45^circ tan"A")`
= `(1 + tan"A")/(1 - tan"A")`
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