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If A + B + C = 180°, prove that sin A + sin B + sin C = ABC4cos A2cos B2cos C2 - Mathematics

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प्रश्न

If A + B + C = 180°, prove that sin A + sin B + sin C = `4 cos  "A"/2 cos  "B"/2 cos  "C"/2`

योग
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उत्तर

L.H.S = (sin A + sin B) + sin C

= `2sin  ("A" + "B")/2 cos(("A" - "B")/2) + 2sin  "C"/2 cos  "C"/2`

= `2cos "C"/2[cos(("A" - "B")/2) + sin  "C"/2]`

= `2cos "C"/2[cos(("A" - "B")/2) + cos  ("A" + "B")/2]`

= `2cos  "C"/2[2cos  "A"/2 cos  "B"/2]`

= `4cos  "A"/2 cos  "B"/2 cos  "C"/2`

= R.H.S

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Trigonometric Functions and Their Properties
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometry - Exercise 3.7 [पृष्ठ १२४]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 3 Trigonometry
Exercise 3.7 | Q 1. (vi) | पृष्ठ १२४

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