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Find the value of sin105°.

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प्रश्न

Find the value of sin105°.

योग
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उत्तर

sin105° = sin(60° + 45°)

sin(A + B) = sinAcosB + cosAsinB

sin(60° + 45°) = sin60°cos45° + cos45°sin 60°

= `sqrt3/2*1/sqrt2 + 1/2*1/sqrt2`

= `sqrt3/(2sqrt2) + 1/(2sqrt2)`

= `(sqrt3 + 1)/(2sqrt2)`

sin(105°) = `(sqrt3 + 1)/(2sqrt2)`

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Trigonometric Functions and Their Properties
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometry - Exercise 3.4 [पृष्ठ १०९]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 3 Trigonometry
Exercise 3.4 | Q 5. (ii) | पृष्ठ १०९

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