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Prove That: 1 Sin ( X − a ) Sin ( X − B ) = Cot ( X − a ) − Cot ( X − B ) Sin ( a − B )

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प्रश्न

Prove that:
\[\frac{1}{\sin \left( x - a \right) \sin \left( x - b \right)} = \frac{\cot \left( x - a \right) - \cot \left( x - b \right)}{\sin \left( a - b \right)}\]

संक्षेप में उत्तर
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उत्तर

\[\text{ RHS }\hspace{0.167em} = \frac{\cot\left( x - a \right) - \cot(x - b)}{\sin(a - b)}\]
\[ = \frac{\frac{\cos(x - a)}{\sin(x - a)} - \frac{\cos(x - b)}{\sin(x - b)}}{\sin(a - b)}\]
\[ = \frac{\sin(x - b) \cos(x - a) - \sin(x - a) \cos(x - b)}{\sin(x - a) \sin(x - b) \sin(a - b)}\]
\[ = \frac{\sin(x - b - x + a)}{\sin(x - a) \sin(x - b) \sin(a - b)}\]
\[ = \frac{\sin(a - b)}{\sin(x - a) \sin(x - b) \sin(a - b)}\]
\[ = \frac{1}{\sin(x - a)\sin(x - b)} \]
 = LHS
Hence proved.

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अध्याय 7: Values of Trigonometric function at sum or difference of angles - Exercise 7.1 [पृष्ठ २१]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 7 Values of Trigonometric function at sum or difference of angles
Exercise 7.1 | Q 29.1 | पृष्ठ २१

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