Advertisements
Advertisements
प्रश्न
Point P (2, -7) is the centre of a circle with radius 13 unit, PT is perpendicular to chord AB and T = (-2, -4); calculate the length of AB.
Advertisements
उत्तर
We know that the perpendicular from the center of a circle to a chord bisects the chord.
∴ AB = 2AT
= 2 x 12 units
= 24 units.
APPEARS IN
संबंधित प्रश्न
If the point P(2, 2) is equidistant from the points A(−2, k) and B(−2k, −3), find k. Also find the length of AP.
Using the distance formula, show that the given points are collinear:
(1, -1), (5, 2) and (9, 5)
Using the distance formula, show that the given points are collinear:
(-2, 5), (0,1) and (2, -3)
Determine whether the points are collinear.
P(–2, 3), Q(1, 2), R(4, 1)
Find the distance of a point (12 , 5) from another point on the line x = 0 whose ordinate is 9.
Find the distance between P and Q if P lies on the y - axis and has an ordinate 5 while Q lies on the x - axis and has an abscissa 12 .
AOBC is a rectangle whose three vertices are A(0, 3), O(0, 0) and B(5, 0). The length of its diagonal is ______.
The distance of the point P(–6, 8) from the origin is ______.
What is the distance of the point (– 5, 4) from the origin?
The distance of the point (5, 0) from the origin is ______.
