Advertisements
Advertisements
प्रश्न
The distance of the point (5, 0) from the origin is ______.
विकल्प
0
5
`sqrt(5)`
52
Advertisements
उत्तर
The distance of the point (5, 0) from the origin is 5.
Explanation:
Distance of the point (5, 0) from the origin is 5 units.
APPEARS IN
संबंधित प्रश्न
If A(5, 2), B(2, −2) and C(−2, t) are the vertices of a right angled triangle with ∠B = 90°, then find the value of t.
Name the type of quadrilateral formed, if any, by the following point, and give reasons for your answer:
(−3, 5), (3, 1), (0, 3), (−1, −4)
Show that the points A (1, −2), B (3, 6), C (5, 10) and D (3, 2) are the vertices of a parallelogram.
Find the circumcenter of the triangle whose vertices are (-2, -3), (-1, 0), (7, -6).
Find the distance between the points
(i) A(9,3) and B(15,11)
Find the distance of the following point from the origin :
(5 , 12)
Find the distance between the following point :
(sin θ , cos θ) and (cos θ , - sin θ)
Find distance of point A(6, 8) from origin.
Find distance between point A(–1, 1) and point B(5, –7):
Solution: Suppose A(x1, y1) and B(x2, y2)
x1 = –1, y1 = 1 and x2 = 5, y2 = –7
Using distance formula,
d(A, B) = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`
∴ d(A, B) = `sqrt(square +[(-7) + square]^2`
∴ d(A, B) = `sqrt(square)`
∴ d(A, B) = `square`
The distance between the points (0, 5) and (–5, 0) is ______.
