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Lim X → 0 E X − 1 + Sin X X - Mathematics

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प्रश्न

\[\lim_{x \to 0} \frac{e^x - 1 + \sin x}{x}\]

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उत्तर

\[\lim_{x \to 0} \left[ \frac{e^x - 1 + \sin x}{x} \right]\]
\[ = \lim_{x \to 0} \left[ \frac{e^x - 1}{x} + \frac{\sin x}{x} \right]\]
\[ = 1 + 1\]
\[ = 2\]

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अध्याय 29: Limits - Exercise 29.1 [पृष्ठ ७१]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 29 Limits
Exercise 29.1 | Q 15 | पृष्ठ ७१

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