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Lim X → 0 E X + 2 − E 2 X - Mathematics

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प्रश्न

\[\lim_{x \to 0} \frac{e^{x + 2} - e^2}{x}\] 

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उत्तर

\[\lim_{x \to 0} \left[ \frac{e^{x + 2} - e^2}{x} \right]\]
\[ = \lim_{x \to 0} \left[ e^2 \left( \frac{e^x - 1}{x} \right) \right]\]
\[ = e^2 \times 1\]
\[ = e^2\] 

 

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अध्याय 29: Limits - Exercise 29.1 [पृष्ठ ७२]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 29 Limits
Exercise 29.1 | Q 31 | पृष्ठ ७२

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