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If f(x)={mx2+nx<0nx+m0≤x≤1nx3+mx>1 For what integers m and n does limx→0f(x) and limx→1f(x) exist?

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प्रश्न

if `f(x) = { (mx^2 + n, x < 0),(nx + m, 0<= x <= 1),(nx^3 + m, x > 1):}`

For what integers m and n does `lim_(x-> 0) f(x)` and `lim_(x -> 1) f(x)` exist?

योग
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उत्तर

(i) At x = 0,

`lim_(x → 0^-) f(x) = lim_(x → 0^-) (mx^2 + n) = n`

`lim_(x → 0^+) f(x) = lim_(x → 0^+) (nx + m) = m`

⇒ m = n

(ii) At x = 1,

 `lim_(x → 1^-) f(x) = lim_(x → 1^-) (nx + m) = n + m = 2m, m ∈ R`

 `lim_(x → 1^+) f(x) = lim_(x → 1^+) (nx^3 + m) = n + m = 2m, m ∈ R`

∴ m = n, for n ∈ R

`lim_(x → 0) f(x) = m, m ∈ R`

`lim_(x → 1) f(x) = 2m, m ∈ R`

Hence, for `lim_(x → 0) f(x)` to exist, m = n must be there; `lim_(x → 1) f(x)` exists for any integer values ​​of m and n.

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अध्याय 12: Limits and Derivatives - EXERCISE 12.1 [पृष्ठ २३९]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 12 Limits and Derivatives
EXERCISE 12.1 | Q 32. | पृष्ठ २३९

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