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Lim X → 0 1 − Cos 2 X 3 Tan 2 X

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प्रश्न

\[\lim_{x \to 0} \frac{1 - \cos 2x}{3 \tan^2 x}\] 

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उत्तर

\[\lim_{x \to 0} \left[ \frac{1 - \cos \left( 2x \right)}{3 \tan^2 x} \right]\]
\[ = \lim_{x \to 0} \left[ \frac{2 \sin^2 x}{3 \tan^2 x} \right]\]
\[ = \lim_{x \to 0} \left[ \frac{2}{3} \times \frac{\sin^2 x}{\sin^2 x} \times \cos^2 x \right]\]
\[ = \frac{2}{3} \cos^2 0\]
\[ = \frac{2}{3}\]

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अध्याय 29: Limits - Exercise 29.7 [पृष्ठ ५१]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 29 Limits
Exercise 29.7 | Q 47 | पृष्ठ ५१

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