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Lim X → a Cos √ X − Cos √ a X − a - Mathematics

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प्रश्न

\[\lim_{x \to a} \frac{\cos \sqrt{x} - \cos \sqrt{a}}{x - a}\] 

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उत्तर

\[\lim_{x \to a} \frac{\cos \sqrt{x} - \cos \sqrt{a}}{x - a}\]
\[ = \lim_{x \to a} \frac{- 2 \sin \left( \frac{\sqrt{x} + \sqrt{a}}{2} \right) \sin \left( \frac{\sqrt{x} - \sqrt{a}}{2} \right)}{2\left( \frac{\sqrt{x} - \sqrt{a}}{2} \right) \left( \sqrt{x} + \sqrt{a} \right)}\]
\[ = \lim_{x \to a} \frac{- \sin \left( \frac{\sqrt{x} + \sqrt{a}}{2} \right)}{\sqrt{x} + \sqrt{a}} \times \frac{\sin \left( \frac{\sqrt{x} - \sqrt{a}}{2} \right)}{\left( \frac{\sqrt{x} - \sqrt{a}}{2} \right)}\]
\[ = \frac{- 1 \sin \left( \sqrt{a} \right)}{2\sqrt{a}} \times 1\]
\[ = \frac{- \sin \sqrt{a}}{2\sqrt{a}}\]

 

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अध्याय 29: Limits - Exercise 29.8 [पृष्ठ ६२]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 29 Limits
Exercise 29.8 | Q 16 | पृष्ठ ६२

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