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प्रश्न
Let A1 A2 A3 A4 A5 A6 A1 be a regular hexagon. Write the x-components of the vectors represented by the six sides taken in order. Use the fact the resultant of these six vectors is zero, to prove that
cos 0 + cos π/3 + cos 2π/3 + cos 3π/3 + cos 4π/3 + cos 5π/3 = 0.
Use the known cosine values to verify the result.

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उत्तर
According to the polygon law of vector addition, the resultant of these six vectors is zero.
Here, a = b = c = d = e = f (magnitudes), as it is a regular hexagon. A regular polygon has all sides equal to each other.
So, \[R_x = A \cos 0 + A \cos \frac{\pi}{3} + A \cos \frac{2\pi}{3} + A \cos \frac{3\pi}{3} + A \cos \frac{4\pi}{3} + A \cos \frac{5\pi}{3} = 0\]
[As the resultant is zero, the x-component of resultant Rx is zero]
\[\Rightarrow \cos 0 + \cos \frac{\pi}{3} + \cos \frac{2\pi}{3} + \cos\frac{3\pi}{3} + \cos \frac{4\pi}{3} + \cos \frac{5\pi}{5} = 0\]

Note: Similarly, it can be proven that
\[\sin 0 + \sin \frac{\pi}{3} + \sin \frac{2\pi}{3} + \sin \frac{3\pi}{3} + \sin \frac{4\pi}{3} + \sin \frac{5\pi}{3} = 0\]
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