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Let A = R – {3}, B = R – {1}. Let f: A → B be defined by f(x) = 𝑥−2𝑥−3 ∀ x ∈ A . Then show that f is bijective. - Mathematics

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प्रश्न

Let A = R – {3}, B = R – {1}. Let f: A → B be defined by f(x) = `(x - 2)/(x - 3)` ∀ x ∈ A . Then show that f is bijective.

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उत्तर

Given that,

A = R – {3}, B = R – {1}

f: A → B be defined by f(x) = `(x - 2)/x` – 3 ∀ x ∈ A

∴ f(x) = `(x - 3 + 1)/(x - 3)` = 1 + `1/(x - 3)`

Let f(x1) = f (x2)

⇒ `1 + 1/(x_1 - 3) = 1 + 1/(x_2 - 3)`

⇒ `1/(x_1 - 3) = 1/(x_2 - 3)`

⇒ x1 = x2

So, (x) is an injection function

Now let y = `(x - 2)/(x - 3)`

⇒ x – 2 = xy – 3y

⇒ x(1 – y) = 2 – 3y

⇒ x = `(2 - 3y)/(1 - y)`

⇒ x = `(3y - 2)/(y - 1)`

⇒ y ∈ R – {1} = B

Since y ∈ R – {1} = B for every y ∈ B, there exists an x ∈ A such that f(x) = y.

Therefore, f(x) is surjective (onto).

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अध्याय 1: Relations And Functions - Exercise [पृष्ठ १२]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 1 Relations And Functions
Exercise | Q 20 | पृष्ठ १२

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