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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

In which of the following molecules carbon atom marked with asterisk (*) is asymmetric? (a) H|.CA∗/..|..∖.I...Br..Cl (b) D|.CA∗/..|..∖.I...Br..Cl (c) H|.CA∗/..|..∖..OH..CA2HA5CHA3 - Chemistry

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प्रश्न

In which of the following molecules carbon atom marked with asterisk (*) is asymmetric?

(a) \[\begin{array}{cc}
\ce{H}\\
|\\
\phantom{.}\ce{C^*}\phantom{}\\
\phantom{}/\phantom{..}|\phantom{..}\backslash\phantom{}\\
\phantom{.}\ce{I}\phantom{...}\ce{Br}\phantom{..}\ce{Cl}
\end{array}\]

(b) \[\begin{array}{cc}
\ce{D}\\
|\\
\phantom{.}\ce{C^*}\phantom{}\\
\phantom{}/\phantom{..}|\phantom{..}\backslash\phantom{}\\
\phantom{.}\ce{I}\phantom{...}\ce{Br}\phantom{..}\ce{Cl}
\end{array}\]

(c) \[\begin{array}{cc}
\ce{H}\\
|\\
\phantom{.}\ce{C^*}\phantom{}\\
\phantom{}/\phantom{..}|\phantom{..}\backslash\phantom{}\\
\phantom{..}\ce{OH}\phantom{..}\ce{C2H5}\phantom{}\ce{CH3}
\end{array}\]

(d) \[\begin{array}{cc}
\ce{H}\\
|\\
\phantom{.}\ce{C^*}\phantom{}\\
\phantom{}/\phantom{..}|\phantom{..}\backslash\phantom{}\\
\phantom{..}\ce{H}\phantom{...}\ce{C2H5}\phantom{}\ce{CH3}
\end{array}\]

विकल्प

  • (a), (b), (c), (d)

  • (a), (b), (c)

  • (b), (c), (d)

  • (a), (c), (d)

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उत्तर

(a), (b), (c)

Explanation:

 Asymmetric/chiral carbon atom is that in which all of its four valencies with four different groups or atoms.

In molecules (a), (b) and (c), all have asymmetric carbon as each carbon has satisfied all four valencies with four different groups or atoms.

In molecule (d), carbon satisfies two of its valencies with two hydrogen atoms i.e., similar atom. So, it is not an asymmetric carbon atom.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Haloalkanes and Haloarenes - Exercises [पृष्ठ १३५]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
अध्याय 10 Haloalkanes and Haloarenes
Exercises | Q I. 9. | पृष्ठ १३५

संबंधित प्रश्न

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Draw the structure of major monohalo products in the following reaction:


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Which is the correct IUPAC name for \[\begin{array}{cc}
\ce{CH3 - CH - CH2 - Br}\\
\phantom{}|\phantom{.......}\\
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\end{array}\]?


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  Column I Column II
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