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In fig., TP = 10 cm, PS = 6 cm. A(ΔRTP)A(ΔRPS)A(ΔRTP)A(ΔRPS) = ? - Geometry Mathematics 2

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प्रश्न

In fig., TP = 10 cm, PS = 6 cm. `"A(ΔRTP)"/"A(ΔRPS)"` = ?

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उत्तर

Draw RE ⊥ TS, T-E-S

ΔRTP and ΔRPS have same height RE.

`"A(ΔRTP)"/"A(ΔRPS)" = "TP"/"PS"`   ......[Triangles having equal height]

`"A(ΔRTP)"/"A(ΔRPS)" = 10/6`    .....[Given]

∴ `"A(ΔRTP)"/"A(ΔRPS)" = 5/3`

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अध्याय 1: Similarity - Q.1 (B)

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