Advertisements
Advertisements
प्रश्न
In each of the following, determine whether the given numbers are roots of the given equations or not; x2 – 5x + 6 = 0; 2, – 3
Advertisements
उत्तर
x2 – 5x + 6 = 0; 2, – 3
When x = 2, then
(2)2 - 5 x 2 + 6
= 4 - 10 + 6
= 10 - 10
= 0
When x = -3, then
(-3)2 -5(-3) + 6
= 9 + 15 + 6
= 30 ≠ 0
∴ x = -3 is not its solution
∴ 2 is root of the equation by -3 is not a root.
APPEARS IN
संबंधित प्रश्न
Solve the equation by using the formula method. 3y2 +7y + 4 = 0
If x=−`1/2`, is a solution of the quadratic equation 3x2+2kx−3=0, find the value of k
Find the values of k for which the roots are real and equal in each of the following equation:
(4 - k)x2 + (2k + 4)x + 8k + 1 = 0
In the following determine the set of values of k for which the given quadratic equation has real roots:
2x2 + kx + 3 = 0
In the following determine the set of values of k for which the given quadratic equation has real roots:
x2 - kx + 9 = 0
Solve the following by reducing them to quadratic equations:
x4 - 26x2 + 25 = 0
Find the value of k so that sum of the roots of the quadratic equation is equal to the product of the roots:
(k + 1)x2 + (2k + 1)x - 9 = 0, k + 1 ≠ 0.
In each of the following, determine whether the given numbers are roots of the given equations or not; 3x2 – 13x – 10 = 0; 5, `(-2)/(3)`
Find the nature of the roots of the following quadratic equations: `x^2 - 2sqrt(3)x - 1` = 0 If real roots exist, find them.
The nature of roots of the quadratic equation 9x2 – 6x – 2 = 0 is ______.
