Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation using formula method only
x2 - 4x - 1 = 0
Advertisements
उत्तर
x2 - 4x - 1 = 0
a =1 ; b = -4 ; c =-1
D = b2 - 4ac
= (-4)2 - 4(1)(-1)
= 16 + 4
= 20
x =`(- "b" ± sqrt ("b"^2 - 4 "ac"))/(2a)`
x = `(4 +- sqrt 20)/2`
x = `(4 +- 2sqrt 5)/2`
x = 2 + `sqrt 5` , x = 2 - `sqrt 5`
APPEARS IN
संबंधित प्रश्न
Find the value of k for which the equation x2 + k(2x + k − 1) + 2 = 0 has real and equal roots.
Find the value of k for which the roots are real and equal in the following equation:
3x2 − 5x + 2k = 0
Find the values of k for which the roots are real and equal in each of the following equation:
2x2 + kx + 3 = 0
Solve the following quadratic equation using formula method only
15x2 - 28 = x
`(2)/x^2 - (5)/x + 2` = 0
Find the value of k so that sum of the roots of the quadratic equation is equal to the product of the roots:
kx2 + 6x - 3k = 0, k ≠ 0
If `(2)/(3)` and – 3 are the roots of the equation px2+ 7x + q = 0, find the values of p and q.
If p, q and r are rational numbers and p ≠ q ≠ r, then roots of the equation (p2 – q2)x2 – (q2 – r2)x + (r2 – p2) = 0 are:
Find the roots of the quadratic equation by using the quadratic formula in the following:
–3x2 + 5x + 12 = 0
Find whether the following equation have real roots. If real roots exist, find them.
`x^2 + 5sqrt(5)x - 70 = 0`
