Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation using formula method only
`2"x"^2- 2 sqrt 6 + 3 = 0`
Advertisements
उत्तर
`2"x"^2- 2 sqrt 6 + 3 = 0`
a = 2 ; b = `- 2 sqrt 6 "x"` ; c = 3
D = b2 - 4ac
= (- 2 sqrt 6)2 - 4(2)(3)
= 12 - 24
= -12
x = `(- "b" ± sqrt ("b"^2 - 4 "ac"))/(2a)`
x = `(2 sqrt 6 +- sqrt -12)/2`
x = `(2 sqrt 6)/4`
x = `sqrt 6/2`
APPEARS IN
संबंधित प्रश्न
If `x=2/3` and x =−3 are roots of the quadratic equation ax2 + 7x + b = 0, find the values of a and b.
Determine the nature of the roots of the following quadratic equation:
9a2b2x2 - 24abcdx + 16c2d2 = 0
Find the values of k for which the roots are real and equal in each of the following equation:
(k + 1)x2 - 2(3k + 1)x + 8k + 1 = 0
For what value of k, (4 - k)x2 + (2k + 4)x + (8k + 1) = 0, is a perfect square.
A quadratic equation with integral coefficient has integral roots. Justify your answer.
Find whether the following equation have real roots. If real roots exist, find them.
8x2 + 2x – 3 = 0
Find the value of 𝑚 so that the quadratic equation 𝑚𝑥(5𝑥 − 6) = 0 has two equal roots.
Compare the quadratic equation `x^2 + 9sqrt(3)x + 24 = 0` to ax2 + bx + c = 0 and find the value of discriminant and hence write the nature of the roots.
Statement A (Assertion): If 5 + `sqrt(7)` is a root of a quadratic equation with rational co-efficients, then its other root is 5 – `sqrt(7)`.
Statement R (Reason): Surd roots of a quadratic equation with rational co-efficients occur in conjugate pairs.
Find the value of k for which the roots of the quadratic equation 5x2 – 10x + k = 0 are real and equal.
