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प्रश्न
In ΔABC right angled at B, AB = 24 cm, BC = 7 m. Determine:
sin C, cos C
योग
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उत्तर
ΔABC is right angled at B
AB = 24cm, BC = 7cm.

Let ‘x’ be the hypotenuse,
By applying Pythagoras
AC2 = AB2 + BC2
x2 = 242 + 72
x2 = 576 + 49
x2 = 625
x = 25
For Sin C, Cos C
sin C = `("AB")/("AC") = 24/25`
cos C = `("BC")/("AC") = 7/25`
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