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In ΔABC right angled at B, AB = 24 cm, BC = 7 m. Determine: sin C, cos C - Mathematics

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प्रश्न

In ΔABC right angled at B, AB = 24 cm, BC = 7 m. Determine:

sin C, cos C

योग
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उत्तर

ΔABC is right angled at B

AB = 24cm, BC = 7cm.

Let ‘x’ be the hypotenuse,

By applying Pythagoras

AC2 = AB2 + BC2

x2 = 242 + 72

x2 = 576 + 49

x2 = 625

x = 25

For Sin C, Cos C

sin C = `("AB")/("AC") =  24/25`

cos C = `("BC")/("AC") = 7/25`

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अध्याय 8: Introduction to Trigonometry - Exercise 8.1 [पृष्ठ १८१]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 10
अध्याय 8 Introduction to Trigonometry
Exercise 8.1 | Q 1.2 | पृष्ठ १८१
आरडी शर्मा Mathematics [English] Class 10
अध्याय 10 Trigonometric Ratios
Exercise 10.1 | Q 2 .2 | पृष्ठ २३

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