Question

In a ΔABC, if DE is drawn parallel to BC, cutting AB and AC at D and E respectively such that AB = 7.2 cm, AC = 6.4 cm and AD = 4.5 cm. Then, AE = ?

विकल्प

• 5.4 cm

• 4 cm

• 3.6 cm

• 3.2 cm

Answer 1

4 cm

Explanation:

Since DE || BC, by the Basic Proportionality Theorem we have `(AD)/(AB) = (AE)/(AC)`. 

Thus, `AE = AC xx ((AD)/(AB))` 

= `6.4 xx ((4.5)/(7.2))`

= 6.4 × 0.625

= 4.0 cm