हिंदी

If z = x + iy, then show that z z¯+2(z+z¯)+b = 0, where b ∈ R, represents a circle. - Mathematics

Advertisements
Advertisements

प्रश्न

If z = x + iy, then show that `z  barz + 2(z + barz) + b` = 0, where b ∈ R, represents a circle.

योग
Advertisements

उत्तर

Given that: z = x + iy

To prove: `z  barz + 2(z + barz) + b` = 0

⇒ (x + iy) (x – iy) + 2(x + iy + x – iy) + b = 0

⇒ x2 + y2 – 2(x + x) + b = 0

⇒ x2 + y2 – 4x + b = 0

Which represents a circle.

Hence proved.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Complex Numbers and Quadratic Equations - Exercise [पृष्ठ ९१]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 5 Complex Numbers and Quadratic Equations
Exercise | Q 8 | पृष्ठ ९१

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the number of non-zero integral solutions of the equation `|1-i|^x  = 2^x`.


Find the value of i49 + i68 + i89 + i110 


Find the value of: x3 –  x2 + x + 46, if x = 2 + 3i


Simplify the following and express in the form a + ib:

`5/2"i"(- 4 - 3 "i")`


Find the value of : x3 + 2x2 – 3x + 21, if x = 1 + 2i


Show that `((sqrt(7) + "i"sqrt(3))/(sqrt(7) - "i"sqrt(3)) + (sqrt(7) - "i"sqrt(3))/(sqrt(7) + "i"sqrt(3)))` is real


Find the value of x and y which satisfy the following equation (x, y∈R).

`(x+ 1)/(1 + "i") + (y - 1)/(1 - "i")` = i


Find the value of x and y which satisfy the following equation (x, y∈R).

If x + 2i + 15i6y = 7x + i3 (y + 4), find x + y


Answer the following:

Simplify the following and express in the form a + ib:

`(3"i"^5 + 2"i"^7 + "i"^9)/("i"^6 + 2"i"^8 + 3"i"^18)`


Answer the following:

Solve the following equations for x, y ∈ R:

(x + iy) (5 + 6i) = 2 + 3i


Answer the following:

Evaluate: (1 − i + i2)−15 


Answer the following:

Evaluate: i131 + i49 


Answer the following:

Find the value of x3 + 2x2 − 3x + 21, if x = 1 + 2i


Answer the following:

Simplify `[1/(1 - 2"i") + 3/(1 + "i")] [(3 + 4"i")/(2 - 4"i")]`


Evaluate: (1 + i)6 + (1 – i)3 


Locate the points for which 3 < |z| < 4.


Find the value of 2x4 + 5x3 + 7x2 – x + 41, when x = `-2 - sqrt(3)"i"`.


Find the value of k if for the complex numbers z1 and z2, `|1 - barz_1z_2|^2 - |z_1 - z_2|^2 = k(1 - |z_1|^2)(1 - |"z"_2|^2)`


The real value of ‘a’ for which 3i3 – 2ai2 + (1 – a)i + 5 is real is ______.


State true or false for the following:

The argument of the complex number z = `(1 + i sqrt(3))(1 + i)(cos theta + i sin theta)` is `(7pi)/12 + theta`.


What is the smallest positive integer n, for which (1 + i)2n = (1 – i)2n?


What is the reciprocal of `3 + sqrt(7)i`.


For a positive integer n, find the value of `(1 - i)^n (1 - 1/i)^"n"`


If |z1| = |z2| = ... = |zn| = 1, then show that |z1 + z2 + z3 + ... + zn| = `|1/z_1 + 1/z_2 + 1/z_3 + ... + 1/z_n|`.


If z1 and z2 are complex numbers such that z1 + z2 is a real number, then z2 = ______.


If |z + 4| ≤ 3, then the greatest and least values of |z + 1| are ______ and ______.


Find `|(1 + i) ((2 + i))/((3 + i))|`.


The value of `(z + 3)(barz + 3)` is equivalent to ______.


A real value of x satisfies the equation `((3 - 4ix)/(3 + 4ix))` = α − iβ (α, β ∈ R) if α2 + β2 = ______.


The smallest positive integer n for which `((1 + i)/(1 - i))^n` = –1 is ______.


Let z be a complex number such that `|(z - i)/(z + 2i)|` = 1 and |z| = `5/2`. Then the value of |z + 3i| is ______.


If a complex number z satisfies the equation `z + sqrt(2)|z + 1| + i` = 0, then |z| is equal to ______.


If α, β, γ and a, b, c are complex numbers such that `α/a +  β/b + γ/c` = 1 + i and `a/α +  b/β + c/γ` = 0, then the value of `α^2/a^2 +  β^2/b^2 + γ^2/c^2` is equal to ______.


If `|(6i, -3i, 1),(4, 3i, -1),(20, 3, i)|` = x + iy, then ______.


Let `(-2 - 1/3i)^2 = (x + iy)/9 (i = sqrt(-1))`, where x and y are real numbers, then x – y equals to ______.


Simplify the following and express in the form a + ib.

`(3i^5 + 2i^7 + i^9)/(i^6 + 2i^8 + 3i^18)`


Find the value of `sqrt(-3) xx sqrt(-6)`


Show that `(-1 + sqrt3i)^3` is a real number.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×