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If Tan θ1 Tan θ2 = K, Then Cos ( θ 1 − θ 2 ) Cos ( θ 1 + θ 2 ) = - Mathematics

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प्रश्न

If tan θ1 tan θ2 = k, then \[\frac{\cos \left( \theta_1 - \theta_2 \right)}{\cos \left( \theta_1 + \theta_2 \right)} =\]

विकल्प

  • \[\frac{1 + k}{1 - k}\]

     

  • \[\frac{1 - k}{1 + k}\]

     

  • \[\frac{k + 1}{k - 1}\]

     

  • \[\frac{k - 1}{k + 1}\]

     

MCQ
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उत्तर

\[\frac{1 + k}{1 - k}\]

\[\frac{\cos( \theta_1 - \theta_2 )}{\cos( \theta_1 + \theta_2 )}\]

\[ = \frac{\cos \theta_1 \cos \theta_2 + \sin \theta_1 \sin \theta_2}{\cos \theta_1 \cos \theta_2 - \sin \theta_1 \sin \theta_2}\]

\[\text{ Dividing numerator and denominator by }\cos \theta_1 \cos \theta_2 ,\text{ we get }:\]
\[\frac{1 + \tan \theta_1 \tan \theta_2}{1 - \tan \theta_1 \tan \theta_2}\]
\[ = \frac{1 + k}{1 - k}\]

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अध्याय 7: Values of Trigonometric function at sum or difference of angles - Exercise 7.4 [पृष्ठ २८]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 7 Values of Trigonometric function at sum or difference of angles
Exercise 7.4 | Q 13 | पृष्ठ २८

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