Advertisements
Advertisements
प्रश्न
If P = − 12x2 – 10xy + 5y2, Q = 7x2 + 6xy + 2y2, and R = 5x2 + 2xy + 4y2 ; find P – Q
Advertisements
उत्तर
P = − 12x2 – 10xy + 5y2
Q = 7x2 + 6xy + 2y2
R = 5x2 + 2xy + 4y2
P − Q = (− 12x2 − 10xy + 5y2) − (7x2 + 6xy + 2y2)
= − 12x2 − 10xy + 5y2 − 7x2 − 6xy − 2y2
= − 12x2 − 7x2 − 10xy − 6xy + 5y2 − 2y2
= − 19x2 − 16xy + 3y2
APPEARS IN
संबंधित प्रश्न
If a = 3, b = 0, c = 2 and d = 1, find the value of abc − bcd + cda
Show that the value of x3 – 8x2 + 12x – 5 is zero, when x = 1.
Simplify:
− (− 4a − 8a)
Simplify:
− m − n − (− m) − m
Fill in the blank:
2t + r − p − q + s = 2t + r − (..................)
Insert the bracket as indicated:
ab + 2bc − 3ac = 2bc − (...............)
If x = 3, y = 2 and z = 1; find the value of xy
If x = a2 – bc, y = b2 – ca, and z = c2 – ab; find the value of ay – bx + cz
Evaluate (2 + x) × y when x = 3, y = 4:
Substitute m = 3 into 5 + \[\frac{m}{2}\]:
