Advertisements
Advertisements
प्रश्न
Find the value of 3ab + 10bc – 2abc when a = 2, b = 5 and c = 8.
योग
Advertisements
उत्तर
a = 2, b = 5, c = 8
∴ 3ab + 10bc − 2abc
= 3 × 2 × 5 + 10 × 5 × 8 − 2 × 2 × 5 × 8
= 30 + 400 − 160
= 430 − 160
= 270
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
State true and false:
`(2"x"-4)/("x"+1)` = − 1, when x = 1
If x = 2, y = 5 and z = 4, find the value of the following:
yx
Simplify:
− m − n − (− m) − m
Simplify:
`3"x"+(2"x"-overline("x"+2))`
Simplify:
x − [y + {x − (y + x)}]
Fill in the blank:
a + b − c + d = a + (...............)
Insert the bracket as indicated:
x − 2y = − (...................)
Insert the bracket as indicated:
ab + 2bc − 3ac = 2bc − (...............)
If P = − 12x2 – 10xy + 5y2, Q = 7x2 + 6xy + 2y2, and R = 5x2 + 2xy + 4y2 ; find P – Q
Simplify:
3x – 8 (5x – 10)
