Advertisements
Advertisements
प्रश्न
Find the value of 3ab + 10bc – 2abc when a = 2, b = 5 and c = 8.
Advertisements
उत्तर
a = 2, b = 5, c = 8
∴ 3ab + 10bc − 2abc
= 3 × 2 × 5 + 10 × 5 × 8 − 2 × 2 × 5 × 8
= 30 + 400 − 160
= 430 − 160
= 270
APPEARS IN
संबंधित प्रश्न
Fill in the blank, when:
x = 3, y = 6, z = 18, a = 2, b = 8, c = 32 and d = 0.
ab + y = ...............
Find the value of 6m − 2n − 5p − 3q, when m = 20, n = 10, p = 2 and q = 9
If a = 3, b = 0, c = 2 and d = 1, find the value of 3a + 2b − 6c + 4d
If x = 2, y = 5 and z = 4, find the value of the following:
`"x"/(2"x"^2)`
Simplify:
25y − (5x − 10y + 6x − 3y)
Simplify:
`"a"-(2"a"-overline(4"a"+3"a"))`
Simplify:
x − (y − z) + x + (y − z) + y − (z + x)
Simplify:
`5{"a"^2-"a"("a"-overline("a"-2))}`
Insert the bracket as indicated:
a − 3b + 5c = a − (..............)
Insert the bracket as indicated:
ab + 2bc − 3ac = 2bc − (...............)
