Advertisements
Advertisements
प्रश्न
Find the value of 3ab + 10bc – 2abc when a = 2, b = 5 and c = 8.
Advertisements
उत्तर
a = 2, b = 5, c = 8
∴ 3ab + 10bc − 2abc
= 3 × 2 × 5 + 10 × 5 × 8 − 2 × 2 × 5 × 8
= 30 + 400 − 160
= 430 − 160
= 270
संबंधित प्रश्न
Fill in the blank, when:
x = 3, y = 6, z = 18, a = 2, b = 8, c = 32 and d = 0.
y − x = ...........
Fill in the blank, when:
x = 3, y = 6, z = 18, a = 2, b = 8, c = 32 and d = 0.
xz + cd = ...................
State true and false:
`(2"x"-4)/("x"+1)` = − 1, when x = 1
If a = 3, find the values of a2 and 2a.
Simplify:
6a2 + (2a2 − a2) − (a2 − b2)
Insert the bracket as indicated:
m2 + x2 − p2 = − (...................)
If x = 3, y = 2 and z = 1; find the value of y2 – x2 + 6z2
If P = − 12x2 – 10xy + 5y2, Q = 7x2 + 6xy + 2y2, and R = 5x2 + 2xy + 4y2 ; find P – Q + R
Simplify:
5 (x + 3y) – 2 (3x – 4y)
In the context of algebra, what is the primary definition of 'substitution'?
