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प्रश्न
If P = − 12x2 – 10xy + 5y2, Q = 7x2 + 6xy + 2y2, and R = 5x2 + 2xy + 4y2 ; find P – Q
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उत्तर
P = − 12x2 – 10xy + 5y2
Q = 7x2 + 6xy + 2y2
R = 5x2 + 2xy + 4y2
P − Q = (− 12x2 − 10xy + 5y2) − (7x2 + 6xy + 2y2)
= − 12x2 − 10xy + 5y2 − 7x2 − 6xy − 2y2
= − 12x2 − 7x2 − 10xy − 6xy + 5y2 − 2y2
= − 19x2 − 16xy + 3y2
संबंधित प्रश्न
Find the value of p + 2q + 3r, when p = 1, q = 5 and r = 2
State true and false:
The value of x + 5 = 6, when x = 1
If x = 2, y = 5 and z = 4, find the value of the following:
`("x"^2"y"^2"z"^2)/"xz"`
Simplify:
(15b − 6b) − (8b + 4b)
Simplify:
(a + b) − (c + d) − (e − f)
Simplify:
`"a"-(2"a"-overline(4"a"+3"a"))`
Simplify:
x − (y − z) + x + (y − z) + y − (z + x)
Simplify:
`"a"−[−{−(a−overline("b"-"c"))}]`
If x = 3, y = 2 and z = 1; find the value of 3x2 − 5y2
Multiply and then evaluate:
(x – 2y + z) and (x – 3z); when x = − 2, y = − 1 and z = 1.
