Advertisements
Advertisements
प्रश्न
Multiply and then evaluate:
(x2 – y) and (xy – y2); when x = 1 and y = 2.
Advertisements
उत्तर
(x2 − y) × (xy − y2)
= x2 (xy − y2) − y (xy − y2)
= x3y − x2y2 − xy2 + y3
Verification:
When x = 1, y = 2
∴ L.H.S. = (x2 − y) (xy − y2)
= [(1)2 − 2] [1 × 2 − (2)2]
= (1 − 2) (2 − 4)
= − 1 × − 2
= 2
R.H.S. = x3y − x2y2 − xy2 + y3
= (1)3 × 2 − (1)2 (2)2 − 1(2)2 + (2)3
= 1 × 2 − 1 × 4 − 1 × 4 + 8
= 2 − 4 − 4 + 8
= 10 − 8
= 2
∴ L.H.S. = R.H.S.
APPEARS IN
संबंधित प्रश्न
Fill in the blank, when:
x = 3, y = 6, z = 18, a = 2, b = 8, c = 32 and d = 0.
c ÷ b = ...........
If a = 3, b = 0, c = 2 and d = 1, find the value of 6a − 3b − 4c − 2d
If a = 3, b = 0, c = 2 and d = 1, find the value of abc − bcd + cda
Simplify:
(15b − 6b) − (8b + 4b)
Simplify:
2m − (3m + 2n − 6n)
Simplify:
3x − [5y − {6y + 2 (10y − x)}]
Fill in the blank:
7x + 2z + 4y − 3 = − 3 + 4y + (.............)
Insert the bracket as indicated:
ab + 2bc − 3ac = 2bc − (...............)
If x = 3, y = 2 and z = 1; find the value of xy + y2z – 4zx
If x = a2 – bc, y = b2 – ca, and z = c2 – ab; find the value of ay – bx + cz
