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प्रश्न
If loge 4 = 1.3868, then loge 4.01 =
विकल्प
1.3968
1.3898
1.3893
none of these
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उत्तर
1.3893
\[\text{ Consider the function } y = f\left( x \right) = \log_e x . \]
\[\text { Let }: \]
\[x = 4\]
\[x + ∆ x = 4 . 01\]
\[ \Rightarrow ∆ x = 0 . 01\]
\[\text { For }x = 4, \]
\[ y = l {og}_e 4 = 1 . 3868\]
\[y = \log_e x\]
\[ \Rightarrow \frac{dy}{dx} = \frac{1}{x}\]
\[ \Rightarrow \left( \frac{dy}{dx} \right)_{x = 4} = \frac{1}{4}\]
\[ \Rightarrow ∆ y = dy = \frac{dy}{dx}dx = \frac{1}{4} \times 0 . 01 = 0 . 0025\]
\[ \therefore \log_e 4 . 01 = y + ∆ y = 1 . 3893\]
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